Page 46 - Fpgee Question And Answer 2024 Edition

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method for obtaining GFR.
= 10 drops/cc
Cu x V = 22.91 drops/2.291cc
CrCl = ℎ
CCr x 1440 = 22.91 drops/min

CrCl = creatinine clearance in ml/min 1204. (b) The amount of sodium hypochlorite is
V = 24-hour urine volume required to prepare 1000cc 0.25% solution:
Cu= concentration of creatinine in urine in mg
CCr= creatinine serum concentration in mg/dL 1000 0.25
= 100 = 2.5
The concentration of creatinine in the urine is 100
mg/dL and 1 dL = 100 cc, therefore We have 5% Dakin (Sodium hypochlorite) solution
in a stock, therefore:
100cc contain 100 mg creatinine
1400 cc contain ? 2.5 100
= 5
1400 100
= = 1400
100 = 50 , 5% ℎ ℎ

1400 x 1400 x 100 1205. (b) The drug is decomposing according to first
CrCl =
2 x 1440 order kinetic, therefore:

68055 ml 68055 ml 2.303 Co
CrCl = = t = log ℎ
day 24 x 60 minutes k C

-2
CrCl = 47.26 ml/minute Co = original concentration = 10
-6
C = concentration at time t = 10
-10
1201. (b) 500cc, 5% Dextrose solutions shall K = rate constant = 2.303 x 10
contain:
2.303 10 −2
500 5 t = −10 log −6
= 25 2.303 x 10 10
100
1
4
1202. (d) 1 in 100 solution is interpreted as 1 gram t = −10 log10
of drug in 100cc of solution. We want to find out 10
how much atropine is required to dispense 1 quart 1
(960cc) , 1 in 100 solution, therefore: t = 10 −10 x 4

960 1 = 9.6 = 9600 t = 40 x 10 ℎ
9
100

1203. (d) 22.91 drops/min 1206. (c) The amount of Triamcinolone in 1%, 1 lb
(454 gm) of ointment:
We need to infuse 20cc + 50cc + 30cc + 1000cc =
1100cc within 8 hours, therefore: = 454 = 4.54 grams Triamcinolone
100
1100
= = 2.291 / If we add 5000 mg of Triamcinolone,
8 60

I.V. set delivers 10 drops/cc, therefore: = 4.54 gm + 5.0 gm

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