Page 50 - Fpgee Question And Answer 2024 Edition

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Atomic mass is designated by the symbol “A.” It is n = molecular weight
the sum of protons (P) and neutrons (N). The empirical formula weight
formula that represents the atomic mass and
atomic number is defined as: n = 116/58 = 2
Therefore, the molecular formula should be:

Where, (C 3H 6O) 2 or C 6H 12O 2

A = Mass number = P + N 1231.(d) The molarity of the solution is defined as
Z = Atomic number = P or Electron (E) the number of moles of solute per 1000 ml or 1 liter
X = Element of the solution. Therefore,

1 M solution = 84 gm NaHCO 3 in 1000 ml
A = Z + N 1 84
63 = Z + 35 2 (0.5)M solution = (42) gm NaHCO 3 in 1000 ml
2
42
Z = 28 0.5 M solution = (10.5) gm NaHCO 3 in 1000 (250) ml
4
4

Therefore, the atomic number for Ni is 28, 28 1232. (d) According to Boyle’s Law, at a constant
protons (P), 35 neutrons (N) and 28 electrons (E). temperature the volume of gas is inversely
proportional to its pressure. It is described as

1228. (b) The molecular weight of methanol follows:

(CH 3OH) is 32 grams/mole. Therefore the number of
moles present in 20 grams of methanol should be: V = K / P where,

Weight in grams V = Volume
Moles = P = Pressure
Molecular weight
K = Constant
20
Moles = = 0.625 moles If at the initial stage the gas has a volume V and
32 1
pressure P at constant temperature, and may
1
1229. (c) The empirical formula represents the change to volume V and pressure P after time ‘t’
2 2
lowest whole number ratio among the atoms of at constant temperature, we can rewrite the
compounds. Therefore, divide by the smaller equation as:
number:
P V = P V
Sn: (0.664/0.664) = 1 1 1 2 2

O: (1.33/0.664) = 2 P = P V / V
2 1 1 2
Therefore, the empirical formula should be SnO 2. = 2 x 100 / 200
= 1 atm = 760 mm Hg
1230. (b) The empirical formula of the compound is
C 3H 6O. Therefore, the empirical formula weight of 1233. (c) To solve this problem, we should use the
the compound is: following equation:

P V P V
1 1
= (3 x C) + (6 x H) + (1 x O) T1 = 2 2
T2
= (3 x 12) + (6 x 1) + (1 x 16)
= 58 Where,

319