Page 13 - Referance Guide For Pharmaceutical Calculations (Naplex, Fpgee and Ptce)
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            159.(d) 10% 100cc solution of Cipro will contain 10   = 5 mg/cc
            gm of active ingredient.                              = 25 mg/5cc

            A patient is taking 500 mg of the drug three times a   163.(c) The amount of hydrocortisone in 240 gm of
            day,  therefore  the  total  amount  of  Cipro  will  be   1% ointment is
            1500 mg per day.
                                                                  = 240 x 0.01
            A number of days = 10000 mg                           = 2.4 gm hydrocortisone
                                  1500 mg
            = 6.66 days.                                          164.(b) 2.5 % w/w

            160.(a) The milligrams of erythromycin required to    = 3 x 100 = 2.5% w/w
            dispense 480cc, 0.25% topical solution are:                 120

            = 480 x 0.25   = 1.2 gm of erythromycin               165.(a) The amount of triamcinolone in 1% 60 gm of
                      100                                         ointment:

            We have 2% erythromycin topical solution in stock:    =   60 x 1 = 0.6 gm triamcinolone
                                                                          100
            = 1.2 x 100 = 60cc solution.
                       2                                          % of Triamcinolone in final mixture:

            161.(a) 166.66cc 3% acetic acid                       = 0.6 x 100   = 0.5% w/w
                                                                           120

                                                                  166.(a) 1 cc of Atropine (0.4 mg) is mixed with 49cc
                                                                  of ocean nasal mist solution:

                                                                  = 0.4 mg/50 cc
                                                                  = 400 mcg/50 cc
            To prepare 3 parts   we need 0.5 parts                = 8 mcg/cc
            To prepare 1000      ?
                                                                  167.(b) The amount of Xylocaine present in 60 gram
            = 1000 x 0.5 = 166.66cc 3% acetic acid                2.5 % ointment:
                       3
                                                                  = 60 x 2.5 = 1.5 gm Xylocaine
            166.66cc  3%  acetic  acid  should  be  mixed  with         100
            (1000-166.66) 833.33cc of water to prepare 1000cc
            of 0.5% acetic acid solution.                         The  number  of  cc  of  10%  Xylocaine  solution
                                                                  required:
            162.(b) 25 mg/5cc.
                                                                  = 1.5 x 100 = 15cc of 10% Xylocaine
            Total milligrams of Amitriptyline:                              10

            = 8 x 150                                             168.(c)“aa” stands for “each of” and therefore the
            = 1200 mg                                             quantity  of  lidocaine  viscous  solution  should  be
                                                                  60cc.
            This amount shall be present in 240cc cherry syrup:
            = 1200 mg/240cc
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