Page 13 - Referance Guide For Pharmaceutical Calculations (Naplex, Fpgee and Ptce)
P. 13
www.pharmacyexam.com Krisman
159.(d) 10% 100cc solution of Cipro will contain 10 = 5 mg/cc
gm of active ingredient. = 25 mg/5cc
A patient is taking 500 mg of the drug three times a 163.(c) The amount of hydrocortisone in 240 gm of
day, therefore the total amount of Cipro will be 1% ointment is
1500 mg per day.
= 240 x 0.01
A number of days = 10000 mg = 2.4 gm hydrocortisone
1500 mg
= 6.66 days. 164.(b) 2.5 % w/w
160.(a) The milligrams of erythromycin required to = 3 x 100 = 2.5% w/w
dispense 480cc, 0.25% topical solution are: 120
= 480 x 0.25 = 1.2 gm of erythromycin 165.(a) The amount of triamcinolone in 1% 60 gm of
100 ointment:
We have 2% erythromycin topical solution in stock: = 60 x 1 = 0.6 gm triamcinolone
100
= 1.2 x 100 = 60cc solution.
2 % of Triamcinolone in final mixture:
161.(a) 166.66cc 3% acetic acid = 0.6 x 100 = 0.5% w/w
120
166.(a) 1 cc of Atropine (0.4 mg) is mixed with 49cc
of ocean nasal mist solution:
= 0.4 mg/50 cc
= 400 mcg/50 cc
To prepare 3 parts we need 0.5 parts = 8 mcg/cc
To prepare 1000 ?
167.(b) The amount of Xylocaine present in 60 gram
= 1000 x 0.5 = 166.66cc 3% acetic acid 2.5 % ointment:
3
= 60 x 2.5 = 1.5 gm Xylocaine
166.66cc 3% acetic acid should be mixed with 100
(1000-166.66) 833.33cc of water to prepare 1000cc
of 0.5% acetic acid solution. The number of cc of 10% Xylocaine solution
required:
162.(b) 25 mg/5cc.
= 1.5 x 100 = 15cc of 10% Xylocaine
Total milligrams of Amitriptyline: 10
= 8 x 150 168.(c)“aa” stands for “each of” and therefore the
= 1200 mg quantity of lidocaine viscous solution should be
60cc.
This amount shall be present in 240cc cherry syrup:
= 1200 mg/240cc
62