Page 29 - Reference Guide For Foreign Pharmacy Licensing Exam Theory
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                   The coefficient of variation or relative variation can be calculated by the following equation:

                        SD
                   Sx =
                        √n

                   Where SX = Standard error of mean,
                                SD =  Standard variation and
                                n = Number of observation.

                   Example: If the SD of an individual value is 2, the standard error of means of size 4 is:

                         2
                   Sx =
                        √4

                   Sx = 1

                   The Binomial and Normal Distribution

                   The Binomial Distribution: It is applicable in data where one of two mutually exclusive and independent
                   outcomes is possible as a result of a single observation or experimental trial.

                   For example, tossing a coin will bring only one outcome at a time, tail or head.

                   The probability of success in n binomial trials can be calculated by the following equation:

                            n
                                x n−x
                   P(x) =  ( ) P q
                            x

                           n
                   Where ( ) =       n !
                           x      x ! (n−x) !

                   p = probability of success ( p + q = 1) and
                   q = probability of failure.

                   Example: Calculate the probability of success that 3 or less of 6 patients will be cured if the probability of
                   cure of an individual patient is 0.8 or 80%.

                            6      3     3
                   P(3) =  ( ) (0.8) (0.2)  where (p + q = 1)
                            3

                                                              6
                   P(3) =   6 x 5 x 4x 3 x 2 x1 x 0.512 x 0.008   where ( ) =    6 !    =    6 x 5 x 4x 3 x 2 x1
                                 (3 x 2 x 1)(3 x2 x 1)        3      3 ! (6−3) !  (3 x 2 x 1)(3 x2 x 1)

                   P(3) =   0.082

                   The probability (p) of exactly 3 cures from 6 patients is 0.082 or 8.19%.





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